200W and 100W bulbs both meant for operation at 220v are connected in series.when connected to a 220 v supply the power consumed by them will be
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200W and 100W bulbs both meant for operation at 220v are connected in series.when connected to a 220 v supply the power consumed by them will be
solution : resistance of first bulb, R1 = V²/P1 = (220)²/200 = 48400/200 = 242 Ω
resistance of 2nd bulb, R2 = V²/P2 = (220)²/100 = 48400/100 = 484 Ω
now both the bulbs are connected in series combination,
so, Req = R1 + R2 = 242 + 484 = 726 Ω
now, current through bulb, i = V/Req
= 220/726 ≈ 0.303A
so, power consumed by them = i²Req
= (0.303A)² × 726 Ω
≈ 66.65 W
hence power consumed by bulbs will be 66.65W
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1
Answer:
66 W
Explanation:
P2=V2/R2
R2=220 SQUARE/P SQUARE
=220 X 220/200
=242
R2= V2/RESISTOR =220 SQUARE / 726
=66 W
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