201.A metallic rod of length 2m is rigidly clamped at its middle point.A longitudinal wave is setup in the rod in such a way that there will be 3nodes on either side of the clamped point.Then the wave length of the longitudinal wave so produced is
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the total number of nodes in half length of the rod = 3
at the two free ends of the rod, there are antinodes.
so half length of the rod = 1 m = 3 * λ/2 + λ/4 = 7 λ/4
λ = 4/7 m
at the two free ends of the rod, there are antinodes.
so half length of the rod = 1 m = 3 * λ/2 + λ/4 = 7 λ/4
λ = 4/7 m
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