Physics, asked by alisha8483, 1 year ago

201. Two cars A and B start moving from the same point
with same speed v = 5 km/minute. Car A moves
towards North and car B is moving towards East. What
is the relative velocity of B with respect to A?
(1) 5√2 km/min towards South-East
(2) 5√2 km/min towards North-West
(3) 5√2 km/min towards South-West
(4) 5√2 km/min towards North-East​

Answers

Answered by Rambhupal01
4

Answer:

1

Explanation:

as car B is moving towards East and A towards North....car B will be in the south-east direction of car A

Answered by sushiladevi4418
6

Answer:

(4) 5√2 km/min towards North-East​

Explanation:

As per the question,

We have been provided that,

Two cars A and B start moving from the same point

with same speed, that is magnitude of A and B are:

V_{A} =V_{B} = 5\ \frac{km}{min}

Therefore,

Relative\ velocity = \sqrt{V_{A}^{2}+V_{B}^{2}}

=  \sqrt{(5)^{2}+(5)^{2}}

= \sqrt{125}

= 5\sqrt{2}\frac{km}{min}

And the direction will be towards  North-East​

Hence, the relative velocity of B with respect to A = 5\sqrt{2}\frac{km}{min}

Therefore, the correct opttion is (4).

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