Question

2010
BER
Week 45 - 309-056
Sunrise : 6.35 am
Sunset : 5.35 pm
day
an
If
with the
object is thrown Vertically up
initial Speed
om the Good nd, then the time
laken.
the object to return back to ground is_______​

Answer 1

Explanation:

Explanation :- case 1 :-when body moves upward direction.

initial velocity =u

final velocity =v=0

now, v=u+at 

Here, v=0,a=−g [acceleration is downward direction]

0=u−gt⇒t=u/g 

Maximum height = h

u2=2gh⇒h=u2/2g---(1)

Case 2 :- when body moves downward direction.[Falling from maximum height]

initial velocity, u=0

final velocity = v

use formula, s=ut+1/2at2

here,s=−h,u=0 and a=−g

−h=0−1/2gt′2

−u2/2g=−gt′2/2 [from equation(1)]

t′=u/g

Hence, total time =t+t′=u/g+u/g=2u/g

Hence,2u/g