Math, asked by praveenagangula8, 11 months ago

20192019×20182019-20182018×20192020​

Answers

Answered by MaheswariS
7

\textbf{Given:}

20192019{\times}20182019-20182018{\times}20192020

\text{Take }x=20192019\;\;\&\;\;y=20182018

\text{Now,}

20192019{\times}20182019-20182018{\times}20192020

=x(y+1)-y(x+1)

=xy+x-xy-y

=x-y

=20192019-20182018

\bf=10001

Answered by slicergiza
2

Answer would be 10001

Step-by-step explanation:

Given expression,

20192019×20182019-20182018×20192020​

Since, the direct multiplication is quite calculative,

So, we need to simply the expression as possible,

∵ 20192020​ = 20192019 + 1

And 20182019 = 20182018 + 1

⇒ 20192019×(20182018 + 1)-20182018×(20192019 + 1)

Using distributive property,

= 20192019×20182018 + 20192019-20182018×20192019 - 20182018

= 20192019 - 20182018

= 10001

#Learn more:

Simplify the expression :

https://brainly.in/question/7625015

Similar questions