2028 - By which smallest number the given number should be multiplied,so that the result becomes a perfect square ? Find the square root of the result obtained.
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Answered by
2
we should x 3 and after multiplying by 3 the number becomes 6084 and its square root is 78
Answered by
4
Solution :
Resolving 2028 into product of prime,
we get ,
2 | 2028
________
2 | 1014
________
3 | 507
________
13 | 169
________
*******13
2028 = 2 × 2 × 3 × 13 × 13
= ( 2 × 2 ) × 3 × ( 13 × 13 )
We see that 2 , 13 exist in pairs .
while 3 is alone .
So , we should multiply the given
number by 3 to get a perfect square.
Therefore ,
the perfect square so obtained is
2028 × 3 = 6084
Now ,
Square root of 6084
= √6084
= √( 2 × 2 )( 3 × 3 )( 13 × 13 )
= 2 × 3 × 13
= 78
Therefore ,
√6084 = 78
•••
Resolving 2028 into product of prime,
we get ,
2 | 2028
________
2 | 1014
________
3 | 507
________
13 | 169
________
*******13
2028 = 2 × 2 × 3 × 13 × 13
= ( 2 × 2 ) × 3 × ( 13 × 13 )
We see that 2 , 13 exist in pairs .
while 3 is alone .
So , we should multiply the given
number by 3 to get a perfect square.
Therefore ,
the perfect square so obtained is
2028 × 3 = 6084
Now ,
Square root of 6084
= √6084
= √( 2 × 2 )( 3 × 3 )( 13 × 13 )
= 2 × 3 × 13
= 78
Therefore ,
√6084 = 78
•••
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