Question

একটি খেলনা গাড়ি 20cm/s বেগে চলছিল। 1 মিটার দূরত্ব যাবার পরে ওই গাড়ির বেগ দাঁড়ালো 50cm/s। গাড়ির ত্বরন নিৰ্ণয় করো।​

Answer 1

The question is "A toy car was moving at a speed of 20cm / s. After going a distance of 1 meter, the speed of the car stopped at 50cm / s. Determine the acceleration of the vehicle?"

Given that,

Initial speed of the car, u = 20 cm/s = 0.2 m/s

Final speed of the car, v = 50 cm/s = 0.5 m/s

Distance covered before stopping, d = 1 m

To find,

Acceleration of the car.

Solution,

The change in velocity divided by time equals acceleration. The mathematical form is given by :

$a=\dfrac{v-u}{t}$

Using third equation of motion,

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0.5)^2-(0.2)^2}{2\times 1}\\\\a=0.105\ m/s^2$

So, the acceleration of the car is $0.105\ m/s^2$.