20cm³ of a solution containing impure 4.4g of NAOH in 1litre was neutralized by 8.0cm³of 0.125M sulphuric acid . calculate the percentage purity of the base and mass of pure sodium hydroxide in impure mass
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Explanation:
mvf=mvf
m(20) = 2
m=0.1 M
w/40=0.1
w=4 gm
mass of pure base = 4 gm
purity of base = 4/4.4
purity of base = 91 percent
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