Question

20g bullet moving 200m/s hits a bag of sand come to rest in 0.00113s

Answer 1

Complete the question please

Answer 2

mass of bullet = 20g=0.02kg

mass of bullet = 20g=0.02kginitial speed of bullet =200m/s

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/s

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0 come to rest = 0.0118

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0 come to rest = 0.0118=(0-200)/0.011

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0 come to rest = 0.0118=(0-200)/0.011= 200000/11m/s2

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0 come to rest = 0.0118=(0-200)/0.011= 200000/11m/s2force =(0.2)(200000)11)

mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0 come to rest = 0.0118=(0-200)/0.011= 200000/11m/s2force =(0.2)(200000)11)= 4000/11

1. mass of bullet = 20g=0.02kginitial speed of bullet =200m/smomentum = mass - velocity =0.02-200kg m/s= 4kg m/sfinal velocity = 0 come to rest = 0.0118=(0-200)/0.011= 200000/11m/s2force =(0.2)(200000)11)= 4000/11= 363.63N