20g of h2so4 is present in 50g of water what is molality of solution
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Answer: 4.08 m is the molality
Explanation:
Moles of 20g H2SO4 = 20/98
Molality = Moles/mass of solvent in kg
= 20/98/50/1000
= 20/98 * 1000/50
= 400/98 = 4.08 m
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