20g of N2 reacts with 5g of H2 find reactant left unreacted
Answers
Answered by
0
Explanation:
Correct option is
C
56g of N
2
+10g of H
2
N
2
(g)+3H
2
(g)→2NH
3
(g)
In the given reaction, 1 mol of N
2
reequires 3 moles of H
2
for the formation fo ammonia.
Thus if the number of moles of N
2
and H
2
should be in ratio 1:3.
We know,
n=
molecular weight
weight
Thus in option C 56g of N
2
means 2 moles of N
2
and 10g of H
2
means 5 moles of H
2
.
Thus here H
2
acts as limiting reagent.
Answered by
0
Answer:
N2+3H2 --- 2NH3.
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