Question

20g of solute is dissolved in 150g of water . calculate the mass of strength​

Answer 1

Answer:

HEY MATE HERE YOU GO

Explanation:

To get the volume, you have to know what the density of the solution is. Determine the percent concentration by mass of the solution first

%w/w=msolute/msolution⋅100

In your case, the mass of the solution will be

m solution=m glucose+m water msolution

=20+150=

170 g

This means that you get

%w/w=20g/170g⋅100

=11.8%

The density of this solution will thus be

= 1.045 g/mL

Use glucose's molar mass to determine how many moles you have

20g⋅1 mole glucose

180.16g

=0.111 moles glucose

The solution's volume will be

170g⋅ 1 mL/1.045g

=162.7 mL

This means that its molarity is - do not forget to convert the volume to liters!

=nV

=0.111 moles/162.7⋅10−3L

=0.68 M

A solution's molality is defined as the number of moles of solute divided by the mass of the solvent - in kilograms! This means that you have

b=n/mwater

=0.111 moles /150⋅10^−3kg

=0.74 molal

To get the mole fraction of sucrose, you need to know how many moles of water you have present. Once again, use water's molar mass

150g⋅1 mole water

18.02g=

8.24 moles water

The total number of moles the solution contains is

ntotal

=n glucose+n water

n total

=0.111+8.24

=8.351 moles

This means that the mole fraction of sucrose, which is defined as the number of moles of sucrose divided by the total number of moles in the solution, will be

χ sucrose

=nsucrose/ntotal

=0.111 moles/8.351moles

=0.013

HOPE THIS HELPSS YOU

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