Question

.20g of sugar is dissolved in 280 g of water. The mass by mass percentage of solution is​

Answer 1

Answer:

80g plz mark as brainlist answer

Answer 2

Provided that:

• Sugar = 20 g
• Water = 280 g

Where, the sugar is solute and the water is solvent.

To calculate:

• Mass percentage

Solution:

• Mass percentage = 6.66 %

Using concept:

• Mass percentage formula

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \%}}}}}}$

Knowledge required:

• Solute is present in less quantity.

• Solvent is present is excess quantity.

• Solution consists of two components that are solute and solvent.

• The component of the solution that dissolves the other component in it is called the solvent.

• The component of the solution that is dissolved in the solvent is called solute.

Required solution:

$:\implies \sf Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \% \\ \\ :\implies \sf Mass \: \% \: = \dfrac{20}{20+280} \times 100 \: \% \\ \\ :\implies \sf Mass \: \% \: = \dfrac{20}{300} \times 100 \: \% \\ \\ :\implies \sf Mass \: \% \: = \dfrac{2}{30} \times 100 \: \% \\ \\ :\implies \sf Mass \: \% \: = \dfrac{1}{15} \times 100 \: \% \\ \\ :\implies \sf Mass \: \% \: = \dfrac{100}{15} \\ \\ :\implies \sf Mass \: \% \: = 6.66 \: \%$

• Henceforth, mass percentage = 6.66 percentage.