20g water at 0c is mixed with 50g water at 100c then find final temperature after mixing.
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H1= 20× 1× (t-0). ( let t be the final temperature of the mixture and the specific heat capacity of water is 1 cal/GM)
H2= 50×1× (100-t)
Now, H1=H2
=> 20×t= 50×100- 50×t
=> 70×t = 5000
=> t= 5000/70= 71.42℃.
H2= 50×1× (100-t)
Now, H1=H2
=> 20×t= 50×100- 50×t
=> 70×t = 5000
=> t= 5000/70= 71.42℃.
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