Question

20kg of N2 and 3kg of h2are mixed to produce NH3. The amount of NH3 formed is

Answer 1

Answer:

16.897 kg NH3 or 992.123 moles NH3

Explanation:

First write a balanced equation for the reaction:

N2 + H2 -> NH3

N2 + 3H2 -> 2NH3

Convert mass in kg to moles using molecular mass:

N2 m.w = 28.0134 g/mol -> 20 kg N2 = 713.944 moles N2

H2 m.w = 2.0159 g/mol -> 3 kg H2 = 1488.184 moles H2

Use moles and stoichiometry to find moles of product (NH3):

H2 is the limiting reagent because 3 * 713.944 > 1488.184

2 * (1488.184) / 3 moles = 992.123 moles NH3

Convert moles of product back to mass in kg:

NH3 m.w = 17.031 g / mol

992.123 mol * (17.031 g / mol) / (1000 g/kg) = 16.897 kg NH3

Answer: 16.897 kg NH3 or 992.123 moles NH3

Note that this assumes 100% yield which in unlikely in a real world scenario.