Question

20m of water is mixed with 30 m of another
Liquid Bith a sp. gravity of 0.9 The volune of
the mixture would be​

Answer 1

Answer:

Let ρ

1

and ρ

2

be the densities of two liquids.

when equal volume of two liquids are mixed , then specific gravity (ρ) is given by ρ =

2

(ρ

1

+ρ

2

)

and when equal masses of two liquids are added ,then specific gravity (ρ) = 2( ρ 1 +ρ 2ρ 1ρ

2 )so we have

2ρ 1+ρ 2= 4 ....................(1)

and 2( ρ1+ρ 2ρ 1×ρ

2 ) = 3 ..........(2)

on solving 1st and 2nd we get ρ

1=6 and ρ 2 =2