Question

20ml of 0.4 M H2SO4and 80 ml of 0.2 M NaOH are mixed. Then, the pH of the resulting solution is​

Answer 1

Answer:

B

1.097

Option B is Correct

Molenumber=Concentration×Volume

MoleofH

2

SO

4

=0.4×20=8

MoleofNaOH=0.2×80=16

8moleofH

2

SO

4

iscompletlyneutralisedby8moleofNaOH.Soremaining8moleofNaOHispresentinthemixture.

[H

+1

]=

Volumeofthesolution

MoleofNaOH

=

80+20

8

=

100

8

=0.08M

P

H

=−log(0.08)=1.097