Question

20ml of 0.4M H2SO4 and 80ml of 0.2M NaOH are mixed. then the PH of the resulting solution is​

Answer 1

Answer

pH = 7

Number of moles = Molarity X Volume

Moles of H2SO4 = 0.02 X 0.4 = 0.008 moles

Moles of NaOH = 0.08 X 0.2 = 0.016 moles

2 moles of NaOH are required to neutralize 1 mole of H2SO4 as 2 moles of H+ ions are generated.

Therefore 0.008 moles of H2SO4 are neutralized by 0.016

Moles of NaOH. Hence the pH of solution will be 7.

Answer 2

Answer:

2 moles of NaOH are required to neutralize 1 mole of H2SO4 as 2 moles of H+ ions are generated. Moles of NaOH. Hence the pH of solution will be 7.

Explanation:

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