Question

20ml of a mixture of C2H2
and CO was exploded with 30ml of oxygen.The gases after the reaction had a volume of 34ml .On treatmentwith KOH,8ml of oxygen remained.Calculate the composition of the mixture.]​

Answer 1

Answer:

6 and 14ml.

Explanation:

C2H2 + 5O2 -> 2CO2 + H2O. So, from the equation we can get that the concentration of CO2 will be 2x if the concentration of C2H2 is taken as x.

So, CO+ 1/2O2 -> CO2 and from here we can say that the concentration of CO2 will be same as CO which is (20-x).

Hence, 2x+20-x +8 will be equal to the volume 34ml. Which on solving we will get x will be 6ml which is C2H2 and 20-6=14 ml of CO.

Answer 2

Answer:

Explanation:

C2H2+5O2→2CO2+2CO2 + H20

x 2x

CO + 1/2O2 → CO2

(20 - x ) ( 20 -x )

2x+20 -x +8 =34

x+28= 34

x=6ml

volume Of C2H2= x = 6mI

volume of CO = 20-x =14 ml

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