20th!!
help..!!!!!! physics exam tomorrow!!
❌❌don't tell that the answers are written... need explanation afterall !!
#sumedhian ❤❤
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Answered by
3
Answer:
(i)Initial velocity = u = 19.6 m/s .
Acceleration due to gravity = g = -9.8 m/s
Time taken to reach the ground = t = 5s
Let assume height of the building is H
then displacement is y direction = S = -H
S = ut + at²/2
-H = (19.6)(5) - (9.8)(25)/2
-H = -24.5
H = 24.5 m
(ii)v=u+at [take acceleration negative because ball is coming down]
v=19.6+(-9.8×5)
v=19.6-49
v=29.4
@Hopeless
Answered by
5
Answer:
(i)Initial velocity = u = 19.6 m/s.
Acceleration due to gravity g= -9.8 m/s
t = 5s
Let assume height of the building is Y
then displacement is y direction = S= -Y
S ut +at/2
Y= (19.6)5) - (9.8)(25)/2
-Y=-24.5
Y = 24.5 m
(i)v=u+at [take acceleration negative
because ball is coming downward to earth]
v=19.6+(-9.8x5)
V=19.6-49
v=29.4
❤️
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