Math, asked by vipulrao2005, 11 months ago

20x^2+2x-1=0
find value of x

Answers

Answered by keerthchinnu5608

0

Step-by-step explanation:

20x^2+2x=1

20x^2+x=1-2

x^2+x=-1/20

x^3=-1/20

x={-1/20}^3

x=0.000125

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