20x- 3 (x-2)=27-6x+2(2x-1)
Answers
Answer:
Step-by-step explanation:
20x-3(x-2)=27-6x+2(2x-1)
We move all terms to the left:
20x-3(x-2)-(27-6x+2(2x-1))=0
We multiply parentheses
20x-3x-(27-6x+2(2x-1))+6=0
We calculate terms in parentheses: -(27-6x+2(2x-1)), so:
27-6x+2(2x-1)
determiningTheFunctionDomain
-6x+2(2x-1)+27
We multiply parentheses
-6x+4x-2+27
We add all the numbers together, and all the variables
-2x+25
Back to the equation:
-(-2x+25)
We add all the numbers together, and all the variables
17x-(-2x+25)+6=0
We get rid of parentheses
17x+2x-25+6=0
We add all the numbers together, and all the variables
19x-19=0
We move all terms containing x to the left, all other terms to the right
19x=19
x=19/19
x=1
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