20x10²⁰electrons flow through a battery of 12V. How much energy is spent by the battery in the
process?
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Answer:
=3844.8 Watt
Explanation:
e = 1.602 * 10^-19C
n= 20 * 10^20
q(No. of Coulomb) =
q = ne
q = 1.602 * 10^-19 * 20 * 10^20
q = 320.4 Coulomb
Ampere:- flow of one coulomb charge per seconds
q = it
i = 320.4 Ampere
P = VI
P = 12 * 320.4
P = 3844.8 Watt
[1 watt = 1 joules/second]
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