Math, asked by pratyushdayal2009, 1 month ago

20y - 3 [10x + 2 {2x - 5 (3x - 2y - x-y)}]

Answers

Answered by brainlyehsanul
86

Step-by-step explanation:

Solution :

20y – 3[10x + 2{2x – 5(3x – 2y – x – y)}]

➡ 20y – 3[10x +2{2x – 15x +10y + 5x +5y}]

➡ 20y – 3[10x + 2{7x – 15x + 15y}]

➡ 20y – 3[10x + 2{–8x + 15y}]

➡ 20y – 3[10x –16x + 15y]

➡ 20y – 3[–6x + 15y]

➡ 20y + 18x – 45y

➡ 18x – 25y.

Answered by hypo12
0

Step-by-step explanation:

20y - 3 [10x + 2 {2x - 5 (3x - 2y - x-y)}]

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