20y - 3 [10x + 2 {2x - 5 (3x - 2y - x-y)}]
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Answered by
86
Step-by-step explanation:
Solution :
20y – 3[10x + 2{2x – 5(3x – 2y – x – y)}]
➡ 20y – 3[10x +2{2x – 15x +10y + 5x +5y}]
➡ 20y – 3[10x + 2{7x – 15x + 15y}]
➡ 20y – 3[10x + 2{–8x + 15y}]
➡ 20y – 3[10x –16x + 15y]
➡ 20y – 3[–6x + 15y]
➡ 20y + 18x – 45y
➡ 18x – 25y.
Answered by
0
Step-by-step explanation:
20y - 3 [10x + 2 {2x - 5 (3x - 2y - x-y)}]
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