Question

(-21) ÷[16+(-13)]+(-5)​

Answer 1

Answer:

-12

Step by step explanation:

FORMULA TO BE USED=BODMAS: B-BRACKET  

O: OF(×)D:DIVISION M:MULTIPLY A:ADDITION  

S:SUBTACTION  

(-21)÷[16+(-13)]+(-5)  

according to the question we have to first solve the bracket =(-21)÷[16-13]+(-5)  

accor.to ques we need to solve division=(-21)÷3+(-5)  

so now we should do addition=(-7) + (-5)  

now we will subtract=7-5  

= -12  

Answer 2

Given: $(-21) \div[16+(-13)]+(-5)$

We have to solve the above expression.

• By using the Bodmas rule, we are solving the above expression.
• As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$(-21) \div[16+(-13)]+(-5)$

$= (-21)/[16+(-13)]+(-5)\\= -21/[16+(-13)]+(-5)\\= -21/[16+-13]+(-5)\\= -21/[16-13]+(-5)\\= -21/[3]+(-5)\\= -21/3+(-5)\\= -21/3+-5\\= -21/3-5\\= -7-5\\= -12$

Hence, we get the solution is$-12$.

NOTE: In this question, we are assuming we have to solve the given expression.

Q. solve$(-21) \div[16+(-13)]+(-5)$