Question

21 3g of Hy react with 29.0 g of O, to give water. The
maximum amount of H2O formed is
(1) 32 g
(2) 7.30 g
(3) 0.73 g
(4) 27 g​

Answer 1

Answer:

First write the chemical equation.

2H₂ + O₂ -----> 2H₂O

For 2H₂ - 2 x 2 = 4 g

O₂ - 32 g

2H₂O - 2 x 18 = 36 g

Now, we have to determine the limiting reagent.

4 g of H₂ reacts with 32 g of O₂

1 g of H₂ reacts with 32/4 g of O₂

3 g of H₂ reacts with 32/4 x 3 = 24 g of O₂

But according to the question, 29 g of O₂ is present.

So, the limiting reactant is hydrogen.

Now, 4 g of H₂ forms 36 g of H₂O

1 g of H₂ forms 36/4 g of H₂O.

3 g of H₂ forms 36/4 x 3 = 27 g of H₂O

Maximum amount of water that can be formed is 27 g.

For, amount of oxygen left of unreacted,

Only 24 g of oxygen will react.

But 29 g is the given amount.

Amount of oxygen unreacted = 29 - 24 = 5 g

Hope This Helps You

Explanation: