Question

(_21)×[5+(_2)]=(_21)×5+(_21)×(_2)​

Answer 1

Step-by-step explanation:

(a) 2(x+4)= 12

x+4\ =\ \frac{12}{2}x+4 =

2

12

x+4 = 6

x= 6-4

x= 2

(b) 3(n-5) = 21

n-5\ =\ \frac{21}{3}n−5 =

3

21

n-5 = 7

n = 7+5

n = 12

(c) 3(n-5) = -21

n-5\ =\ -\frac{21}{3}n−5 = −

3

21

n-5 = -7

n= -7+5

n = -2

(d) 3-2 (2-y) = 7

-2 (2-y) = 7-3

-2(2-y) = 4

2-y\ =\ \frac{4}{2}2−y =

2

4

2-y = 2

-y = 2 -2

y = 0

(e) 4(2-x) = 9

-4\times2-x\times\left(-4\right)\ =\ 9−4×2−x×(−4) = 9

-8+4x = 9

4x= 9+8

x=\ \frac{17}{4}x=

4

17