21.5 g of Nacl dissolves in 60g of water at 25 degree celsius . calculate the solubility of Nacl in water at that temperature.
Answers
Answered by
29
60 g of water dissolved in 21.5 g of NaCl
then....100 g will get dissolved in
21.5/60 * 100
⇒ 35.83 g
∴ solubility is 35.83 g at that temperature.
then....100 g will get dissolved in
21.5/60 * 100
⇒ 35.83 g
∴ solubility is 35.83 g at that temperature.
Answered by
0
Answer:
35.83
Explanation:
potassium=21.5gram
water=60gram
solubility=solute/solvent*100
=21.5/60*100
=35.83gram
answer=35.83gram
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