21.5 g of sodium chloride dissolves in 60g of water at 25oC. Calculate the solubility of sodium chloride at that temperature.
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Answered by
350
Here, mass of solute = 21.5g whereas mass of solvent is 60g.
Given, the temperature of solubility is 25 degree Celsius.
Since, Mass of solute/ mass of solvent x temperature = solubility of the mixture
Solubility of the mixture = 21.5/60 x 25 = 8.96
Given, the temperature of solubility is 25 degree Celsius.
Since, Mass of solute/ mass of solvent x temperature = solubility of the mixture
Solubility of the mixture = 21.5/60 x 25 = 8.96
Answered by
177
HEY!!
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▶Solubility of a Solute = (Wt. of Solute in Sat. Soln. / Wt of Solvent in Sat. Soln.) X 100
✔(21.5/60) X 100
✔35.833 g/100 g of Water.
▶▶As water has density 1g/cc solubility is expressed as 35.833 g/100mL of water
____________________________
▶Solubility of a Solute = (Wt. of Solute in Sat. Soln. / Wt of Solvent in Sat. Soln.) X 100
✔(21.5/60) X 100
✔35.833 g/100 g of Water.
▶▶As water has density 1g/cc solubility is expressed as 35.833 g/100mL of water
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