21.6 gram of silver coin is dissolved in hno3.when nacl is added to this solution all silver is precipitated as agcl.the weight of agcl is found to be 14.35 gram then %of silvar in coin is
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Fraction of Ag in AgCl = 107.9/143.3= 0.753 weight of Ag in 7.20 g AgCl
= 0.753 × 7.20 g = 5.42 g Ag
Hence the 5.82 g coin contains 5.42 g Ag = 0
Fraction of Ag in coin = 5.42 g/5.82 g
= 0.931 = 93.1 % Ag
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