21/8, 5/16 find the quadratic polynomial who sum and product respectively of the zeros are as given.
Answers
Answered by
519
Let the zeroes be à and ß
Sum of zeroes = 21/8
=> à + ß = 21/8
Product of zeroes = 5/16
=> as = 5/16
The required quadratic polynomial is
→ k {x² - (à+ß)x + aß}
→ k {x² - (21/8)x+5/16}
→ k {x²-42x/16 + 5/16}
Put k = 16
→ 16x²-42x+5
Hope it helps....
Sum of zeroes = 21/8
=> à + ß = 21/8
Product of zeroes = 5/16
=> as = 5/16
The required quadratic polynomial is
→ k {x² - (à+ß)x + aß}
→ k {x² - (21/8)x+5/16}
→ k {x²-42x/16 + 5/16}
Put k = 16
→ 16x²-42x+5
Hope it helps....
vishwanath3:
thanks
Answered by
242
Hey there !
The zeroes be α and ß
Sum of zeroes = α + β = 21/8
Product of zeroes = αβ = 5/16
The required quadratic polynomial is
k {x² - (α+ß)x + aß}
k {x² - (21/8)x+5/16}
k {x²-42x/16 + 5/16}
here ,
k = 16
16{x²-42x/16 + 5/16}
16x² - 42x + 5 ----> required polynomial
The zeroes be α and ß
Sum of zeroes = α + β = 21/8
Product of zeroes = αβ = 5/16
The required quadratic polynomial is
k {x² - (α+ß)x + aß}
k {x² - (21/8)x+5/16}
k {x²-42x/16 + 5/16}
here ,
k = 16
16{x²-42x/16 + 5/16}
16x² - 42x + 5 ----> required polynomial
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