Math, asked by vishwanath3, 1 year ago

21/8, 5/16 find the quadratic polynomial who sum and product respectively of the zeros are as given.

Answers

Answered by snehitha2
519
Let the zeroes be à and ß

Sum of zeroes = 21/8

=> à + ß = 21/8

Product of zeroes = 5/16

=> as = 5/16

The required quadratic polynomial is

→ k {x² - (à+ß)x + aß}

→ k {x² - (21/8)x+5/16}

→ k {x²-42x/16 + 5/16}

Put k = 16

→ 16x²-42x+5

Hope it helps....

vishwanath3: thanks
Answered by Anonymous
242
Hey there !

The zeroes be α and ß

Sum of zeroes = α + β =  21/8

Product of zeroes = αβ =  5/16


The required quadratic polynomial is

 k {x² - (α+ß)x + aß}

 k {x² - (21/8)x+5/16}

 k {x²-42x/16 + 5/16}


here , 
 k = 16

16{x²-42x/16 + 5/16}

 16x² - 42x + 5                  ----> required polynomial
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