Question

21. (a - 1)x + 3y = 2,
6x + (1 - 2b) y = 6.
find a and b which has infinite no. of solution
plzz ans the question fast ​

Answer 1

Step-by-step explanation:

if x and y variable are free so a and b have infinite solution

Answer 2

(a-1)x+3y=2 (a-1)x+3y-2=0 since alx+by+(-C1)=0 so here a1=(a-1),b1=3,c1=-2

now 6x+(1-2b)y=6 6x+(1-2b)y-6=0 sin 2x+b2y+(-c2)=0 here a2=6,b2=(1-2b),c2=-6 Now for infinite solution we need a1/a2=b1/b2=c1/02 (a-1)/6=3/(1-2b)=-27-6 first we will take b1/b2=c1/02

i.e. 3/(1-2b)= 2/6 2(1-2b)=18 2-4b=18

-4b=18-2=16 b=-4

Now we will take a1/a2=b1/b2

i.e.a-1/6=3/9. (b=-4) =>3(a-1)=6. (3/9=1/3)

3a-3=6

3a=6+3

a=3