Question

21.
A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails
of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance
R = 192 as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic
field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit
after 1 millisecond is x * 10-A, where the value of x is
[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.
Given : e' = 0.37 , where e is base of the natural logarithm]

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

A 10 cm long perfectly conducting wire PQ is moving with a velocity 1 cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L=1 mH and a resistance R=1Ω as shown in figure. The horizontal rail, L and R lie in the same plane with a uniform magnetic field B=1T perpendicular to the plane. If the key S is closed at certain instant , the current in the circuit after 1 millisecond is x×10

−3

A, where the value of x is ____ .

[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given : e

−1

=0.37, where e is base of the natural logarithm]

Explanation:

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