Question

21. a. A Compound is found to contain 54.67% of carbon, 9.1% of Hydrogen, and the remaining is oxygen. Vapour density of the compound is 22. Calculate its molecular

formula​

Answer 1

Answer:

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Explanation:

Let amount of organic = 100 gm

amount of carbon = 54.55 g

amount of hydrogen = 9.09 g

Amount of oxygen = 36.26 g

number of mole of carbon =

12

34.55

=4.54583

number of mole of hydrogen =

1.018

9.09

=9

number of mole of oxygen =

16

36.26

=2.26

4.54833:9:2.26

2:4:1

organic compounds Empirical formula

=C

2

H

4

O

Molecular weight = 24+4+16=44

(for empirical)

Molecular weight = 2× vapour density

=2×44=88 g

To molecular formula be = C

4

H

8

O

2

Answer 2

Answer:

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Explanation:

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