Question

21. A ball is thrown at an angle o with the horizontal. Its
horizontal range is equal to its maximum height. This
is possible only when the value of tan o is
(1) 4
(2) 2
(3) 1
(4) 0.5
pls answer step wise and with reason... thanks
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Answer 1

Answer:

4

Explanation:

dividing the eqn of max height by eqn of range we get

H÷R = tan o ÷ 4

for H=R ,tan o should be 4 so that it becomes 4÷4=1.which gives H = R