Question

21. A body, moving in a straight line under a constant
acceleration, covers a distance of 12 m in 2nd second and
40 m in fourth second.
(i) Find initial velocity and acceleration of the body.
(ii) Distance moved by the body in next 4 s after 5 s.
Ans.(i) 6 m/s, 4 m/s2 (ii) 136 m.​

Answer 1

Answer:

I can give u formula S=u+a/2g(2n-1)

Explanation:

where n =nth second

write the equation for both time and compare.

I hope you can solve it because I can