Question

(21) A body moving with uniform acceleration is having
velocity 2 m/s and 8 m/s at t = 1 s and t = 4 s.
respectively. Then average velocity of particle in the
time interval t = 1 ş to t = 4 s, is
(1) 2 m/s
(2) 3 m/s
(3) 5/3 m/s
(4) 5 m/s​

Answer 1

Answer:

5m/s

hope it would be correct

Answer 2

Option (4) is correct that is 5 m/s

Explanation:

• Uniform motion is defined as equal distance covered in equal interval of time. In uniform accelerated motion we have constant acceleration throughout the motion

                          Acceleration = $\frac{change in velocity}{time taken}$

                          Acceleration = $\frac{final velocity-initial velocity}{time taken}$

Given, initial velocity = 2 m/s

final velocity = 8 m/s

initial time = 1 s

final time = 4 s

total time taken = 4-1 = 3 s

=> Acceleration = $\frac{8-2}{4-1}$

=> Acceleration = $\frac{6}{3}$

=> Acceleration = 2 ms⁻²

Average velocity = $\frac{total displacement}{total time}$

Distance covered for t=0 to t=1 sec

=> s = u t+$\frac{1}{2} at^{2}$

=> s = 0 *1 + $\frac{1}{2} (2)1^{2}$

=> s = 1 m

Distance covered from t=0 to t= 4 sec

=> s = u t+$\frac{1}{2} at^{2}$

=> s = 0*4 + $\frac{1}{2} (2)4^{2}$

=> s = 16 m

Total distance or displacement = 16 -1 = 15 m

Total time taken = 4-1 = 3 sec

=> Average velocity = $\frac{15}{3}$

=> Average velocity = 5 ms⁻¹

Option (4) is correct

To know more average velocity, visit:

Define average speed and average velocity.

https://brainly.in/question/3912118

Define: average speed and average velocity.

https://brainly.in/question/748452