21. A hollow metal pipe is 77 cm long whose inner radius is 2 cm and outer
radius is 2.2 cm. Find the total surface area of the pipe.
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Answered by
5
Answer:
Given:
⇒Inner radius =
2
4
=2 cm =r
1
⇒Outer radius =
2
4.4
=2.2cm =r
2
⇒Height =77 cm
Solution:
(i) Curved S.A=2πr
1
h (inner)
=2×
7
22
×2×77=968 cm
2
(ii) Curved S.A (outer)=2πr
2
h
=2×
7
22
×2.2×77cm
2
=(22×22×2.2) cm
2
=1064.8cm
2
(iii) Total S.A of pipe = CSA of inner surface + CSA of outer surface + Area of circural base and top
=968+1064.8+2π((2.2)
2
−2π(2)
2
)
=2032.8+5.28 cm
2
=2038.08 cm
2
Answered By
toppr
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