Question

21. A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son
Find their present ages.
man is 28 man older than his son. After 10 vears, he will be thrice as old as his son. Find their​

Answer 1

Answer:

22years = son

44 years = father

Step-by-step explanation:

Answer 2

Given :-

• A man is twice as old as his son. 20 years ago, the age of man was 12 times the age of the son

To Find :-

• What are their present ages

Solution :-

Let, the present age of son be x years

And, the present age of man will be 2x years

According to the question :

⇒ $\sf 12(x - 20) =\: 2x - 20$

⇒ $\sf 12x - 240 =\: 2x - 20$

⇒$\sf 12x - 2x =\: - 20 + 240$

⇒ $\sf 10x =\: 220$

⇒$\sf x =\: \dfrac{\cancel{220}}{\cancel{10}}$

➠$\sf\bold{\purple{x =\: 22\: years}}$

Hence, the required ages are,

✧ Present age of son = x = 22 years

✧ Present age of man = 2x = 2 × 22 = 44 years

∴ The present age of son is 22 years and the present age of man is 44 years.

${\red{ \boxed{\large {\bold{VERIFICATION :-}}}}}$

$↦ \sf 12(x - 20) =\: 2x - 20$

$↦ \sf 12x - 240 =\: 2x - 20$

By putting x = 22 we get,

↦ $\sf 12(22) - 240 =\: 2(22) - 20$

↦$\sf 12 \times 22 - 240 =\: 2 \times 22 - 20$

↦ $\sf 264 - 240 =\: 44 - 20$

↦$\sf 24 =\: 24$

➦ LHS = RHS

Hence, Verified ✔