Math, asked by rishikaahuja436, 2 months ago

21. A man left * 45909 for his sons Alok and Dikshit who are 15 and 13 years old in such a way that
if their shares be invested in 2% C.I., they receive equal amounts on reaching 18 years of age.
How did he divide the money ?​

Answers

Answered by dkchakrabarty01
2

Answer:

Alok,15 years=p amount 18-15=3years

Dikshit, 13 years =q amount 18-13=5years

Let them receive R when they become 18

For Alok R =p(1+2/100)^3=p(1.02)^3

For Dikshit R =q(1+2/100)^5

p(1.02)^3 = q(1.02)^5

p = q(1.02)^2=q(1.0404)

p+q =45909

q(1.0404)+q=45909

q(1.0404+1) = 45909

q(2.0404)=45909

q=45909/2.0404=22500 Dikshit's share

p= 45909-22500=23409 Alok's share

Answered by shilamore12345
0

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