Question

)
21) A man walks at a speed of 3 km/hour from location A towards east for 1 hour and
then turning left walks at a speed of 1.5 km/hour for 6 hours towards north to a location
B. The shortest distance between locations A and B is

(A)10km
(B)
12 km
c
~8.54 km​

Answer 1

The speed of man in east direction = 3 km/hr

The speed of man in north direction = 1.5 km/hr

Time taken is taken by a man in east direction = 1 hour

Time taken is taken by a man in north direction = 6 hour

Formula used:

Distance = Speed × Time

Concept used:

The Hypotaneous is the shortest distance while travelling through the right angle

Calculation:

F1 Abhishek Pandey 28-1-2021 Swati D1

The distance covered by man in east direction = 3 × 1 = 3 km

The distance covered by man in North direction = 1.5 × 6 = 9 km

The shortest distance between point A and B = √(32 + 92) = 9.48

∴ The shortest distance between point A and B is 9.48 km .

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