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A potentiometer having a wire 3 m long is connected to the primary circuit containing a battery of 3 volt.
A Leclanche cell gives a null point at 145 cm and a Daniel cell at a point 110cm. The ratio of e.mf.s of
the two cells is
lal
a) 29:22
b) 30 : 37
c) 45 : 67
d) 45: 76
Answers
Answered by
0
Answer:
Given: E
1
=ρl
1
E
1
+E
2
=ρl
2
Formula used for solution
E
2
E
1
=
l
2
l
1
E
1
E
1
+E
2
=
ρl
1
ρl
2
=
l
1
l
2
1+
E
1
E
2
=
l
1
l
2
E
1
E
2
=
l
1
l
2
−1=
l
1
l
2
−l
1
∴
E
2
E
1
=
l
2
−l
1
l
1
=
480−280
280
=
200
280
E
1
:E
2
=7:5
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