Question

21. A ray of light is refracted through a prism in the position of minimum deviation. The
angle of prism 60° and its refractive index 1.532. Calculate the angle of incidence & min
deviation.​

Answer 1

Minimum deviation δ=2i−A

where A is prism angle A=60°

For minimum angle the angle of refraction should be half of prism angle.

So r=A/2=30°

now using the snell's law

nair sini=nglass sinr

sini=1.5sin30

i=48.6° , incidence angle

Minimum deviation δ=2i−A

δ=2×48.6−60=37.9°

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Answer 2

Answer:

answer is 40 degree.......