21. A Source of sound is moving with a velocity of 50ms-1 towards a stationary listener measures the frequency
of the source as 1000HZ.what will be the apparent frequency of the source when it is moving away from the
listener after crossing him?(Velocity of sound in the medium is 330ms!) pls give correct answer
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Answer:
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f
app
=(
V−50
v−0
)f
source
1000=(
300
350
)f
source
f
source
=
350
1000×300
f
app
=(
V+50
V
).f
source
=
400
350
×1000×
350
300
=750Hz ...... hope it's helpful follow me
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