Question

21. A stone is dropped from a height of 122.5m. The distance travelled by it in the last one second of its motion will be:
(1) 23.1 m
(2) 44.1 m
(3) 35.1 m
(4) 54.1 m​

Answer 1

23 .1 m is the distance travelled by it in the last one second of its motion

I hope that my answer is helpful to you

Answer 2

Answer:

A stone is dropped from a height of 122.5 cm. the distance travelled by it in the last one sec of its motion will be 44.1 m

Explanation:

Given:

Height from which stone is dropped: 122.5m that is s

We will use the formula for distance to find the time

that is $s=\frac{1}{2} at^{2}$

Therefore, 122.5= (1/2)(9.8)$t^{2}$

t=5 seconds.

Distance travelled in last second is

Total distance- distance travelled in 4 sec

=$122.5-(\frac{1}{2}\times9.8\times16)$

$=122.5-78.4\\=44.1 m$

Hence, a stone is dropped from a height of 122.5 cm. the distance travelled by it in the last one sec of its motion will be 44.1 m