21. A train travels at a certain average speed for a distance of 63 km and then travels
at a distance of 72 km at an average speed of 6 km/hr more than its original
speed. If it takes 3 hours to complete total journey, what is the original average
speed ? (CBSE 2018-4M)
© E Mallikarjuna Reddy, TGT (Mathematics), Sainik School Kalikiri
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Let original speed of the train be x km/h.
Time taken to travel 63 km = 63/x hours
New speed = (x + 6) km/hr
Time taken to travel 72 km = 72/(x + 6) hours
According to the question
63/x + 72/(x + 6) = 3
x2 - 39x - 126 = 0
(x - 42)(x + 3) = 0
x = -3 or x = 42
As the speed cannot be negative , x = 42
Thus , the average speed of the train is 42 km/ h
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