Question

21. An a particle is moving along a circle of radius R with a
constant angular velocity o. Point A lies in the same plane at
a distance 2R from the centre. Point Arecords magnetic field
produced by a particle. If the minimum time interval between
two successive times at which A records zero magnetic field
is t, the angular speed w, in terms oft is
(a) 2π/t,b)2π/3t,c)π/3t ,d)π/t​

Answer 1

Explanation:

W=omega∆=angle in radian As b=0 so DL*r must be 0 by boot savart law so ∆= 0 or pieTangent to circle of radius r from 2r,0 centered at origin Will be of slope +-0.5 so it subteds a total angleangle ∆( 2pie /3)At origin so W=∆/tW=2pie /3t

Answer 2

Explanation:

Consider the circular motion of the α particle , Given their are two points in he circle where  their is 0 magnetic field.

Two points are drawn and joined with the point A ,where length of one side is R and the other side is 2R  .Therefore the total angle is 120⁰ ie 2π/3 rad.

We know that ω = Total distance / Total time

                       ω  = 2π/3t

                          Hope you understand

This is Habel SAbu ..... Isn't it the Brainliest