Question

21. An electric lamp whose resistance is 8 ohms and a conductor of 2 ohms resistance are
connected in series to a 5 volt battery. Calculate
A. The total resistance of the circuit
B. The current through the circuit
С. The potential difference across the electric lamp and the conductor​

Answer 1

Answer:

Explanation:

The total resistance of the circuit is sum of the resistances or 8+2 =10 ohms

A.10 Ohms

we know, by ohms law,

V=IR => V/R=I => 5/10 A => 0.5 A

B.0.5 A

PD across electric lamp = IR = 0.5X8 = 4V

PD across conductor = IR = 0.5 X 2 = 1V

C. 4V, 1V

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