21. An urn contains 9 red, 7 black and 5 white balls. If three balls are
drawn one after the other without replacement find the probability
that they are red, black and white respectively.
3/76
Answers
Answered by
3
Step-by-step explanation:
Total no. of balls = 9+7+5 = 21
PE of red balls = 9/21 = 3/7
PE of black balls = 7/21 = 1/3
PE of white balls = 5/21
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Answered by
7
hey bro i give your ans
first of all know the type of questions
this is a question of one after one without replacement
so probablity is
get red 9/21
get black 7/20
get white 5/19
multiple it
9×7×5 / 21×20×19
3/76
pls like it and mark as brainliest
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