Question

21) Assertion : x + y - 4 = 0 and 2x + ky - 3 = 0 has no solution if k = 2 Reason: a x + by + c = 0 and a2x + b2y + c2 = 0 are consistent if A1/A2 Not equal to b1/b2​

Answer 1

Answer:

i hope its helpful for u mark it brainliest answer

Step-by-step explanation:

Forthelinestobeparallel

a

2

a

1

=

b

2

b

1



=

c

2

c

1

.

Theequationsarex+y−4=0and2x+ky−3=0.

Herea

1

=1,b

1

=1andc

1

=−4.

a

2

=2,b

2

=kandc

2

=−3.

∴

a

2

a

1

=

2

1

,

b

2

b

1

=

k

1

,

c

2

c

1

=

−3

−4

=

3

4

.

So

k

1

=

2

1

⇒k=2

Sotheassertioniscorrect.

Butwhen

a

2

a

1



=

b

2

b

1

,theequationhasauniquesolution.

So,thesystemisconsistent.

Sothisreasonistrue.

∴Thereasondoesnotexplaintheassertioncorrectly.

Ans−OptionB.

Answer 2

Answer:

b option is correct

Step-by-step explanation:

b option is correct